You are given $5 m$ length of heating wire, it has resistance of $24 \Omega$. It is cut into two and connected to $110$ volt line individually. The total power for the two half lengths is:

Resistance of the full wire $= 24 ohm$

Since resistance is directly proportional to length.

$\therefore$ Resistance of the half wire $= \displaystyle\frac{1}{2} \times 24 = 12 ohm$

Power in one half $= V. I.$

and $V=IR$

$I=\dfrac{V}{R}$

$V=110volts$

$R=12ohms$

Power in one half= $= 110 \times \displaystyle\frac{110}{12}$

$= 55 \times \displaystyle\frac{55}{3} watts$

Total power of two half lengths $= 2 \times 55 \times \displaystyle\frac{55}{3} = \displaystyle\frac{6050}{3}$

= 2016.67 watts

$= 2000 watts$ (approximately)