Plot $(3, 0), (5, 0)$ and $(0, 4)$ on cartesian plane. Name the figure formed by joining these points and find its area.

Find the value of $m$ if the points $(5, 1), (2, 3)$ and $(8, 2m )$ are collinear.

If area of a triangle is $35$ square units with vertices $\left( {2, - 6} \right),\,\,\left( {5,\,\,4} \right)$ and $({k},\,\,4)$ then ${k}$ is :

The area of the triangle whose co-ordinates are $(2012, 7), (2014, 7)$ and $(2014, a)$ is $1 \,sq$ unit. The sum of possible values of $a$ is

If the area of a triangle formed by the points (k, 2k) (-2, 6) and (3, 1) is 20 square units. Find the value of k.