$h(x)=e^{x}$

দৃশ্যকল্প-I: $y(x+1)(x+2)-x+4$

দৃশ্যকল্প-II: $\mathrm{g}(\mathrm{x})=3 \mathrm{x}^{3}-6 \mathrm{x}^{2}-5 \mathrm{x}+1$

$\mathrm{H}(\mathrm{x})=\frac{4}{\mathrm{x}}+\frac{36}{2-\mathrm{x}}, \mathrm{u}(\mathrm{x})=\mathrm{x}^{2}$

দৃশ্যকল্প-১ : $\mathrm{y}=\left(\cos ^{-1} \mathrm{x}\right)^{2}$ এবং দৃশ্যকল্প-২: $\frac{\mathrm{x}}{\ln \mathrm{x}}$

$\left[f(z)=\tan z, h(u)=u^{4}-\frac{2}{3} u^{3}-2 u^{2}+2 u\right.$