Find derivative of given function w.r.t. the respective independent variable $y= \frac{(sinx+cosx)}{cosx}$

If $y=\sqrt{\dfrac{1-\sin 2x}{1+\sin 2x}}$, then $\left(\dfrac{dy}{dx}\right)_{x=0}=$

$\mathbf{g}(\mathrm{x})=\cot ^{-1} \mathrm{x}$;

d/dx of g(x)=?

$\mathbf{f}(\mathbf{x})=\tan x$

$\mathrm{y=cosx}$ এর ক্ষেত্রে-

i. $\mathrm{y}_{1}=-\sin \mathrm{x}$

ii. $\mathrm{y}_{1}\left(\frac{\pi}{2}\right)=-1$

iii. $\mathrm{y}_{2}=\cos \mathrm{x}$

নিচের কোনটি সঠিক?